FE4RACCOONS

FE Civil formula finder

138 FE Civil formulas, with the FE Reference Handbook page to find each one on exam day, what every symbol means, and when to reach for it.

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All 138 formulas

A few formulas are marked not in the handbook. NCEES leaves out basic formulas and definitions it expects you to know, so learn those by heart.

Mathematics & Computational Tools

Study guidePractice problems

Slope from Two Points

Handbook 10.6, p. 37
m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

Find how steep a straight line is when you know two points on it.

mm
slope of the line, rise over runy units per x unit (unitless when both axes share a unit)
x1x_1
x coordinate of the first pointany consistent unit
y1y_1
y coordinate of the first pointany consistent unit
x2x_2
x coordinate of the second pointany consistent unit
y2y_2
y coordinate of the second pointany consistent unit

Watch out: Subtract in the same order on top and bottom (point 2 minus point 1 both times), or the sign of the slope flips.

Distance Formula

Handbook 10.6, p. 37
d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Find the straight-line distance between two points on a plane.

dd
straight-line distance between the two pointssame unit as the coordinates
x1x_1
x coordinate of the first pointany consistent unit
y1y_1
y coordinate of the first pointany consistent unit
x2x_2
x coordinate of the second pointany consistent unit
y2y_2
y coordinate of the second pointany consistent unit

Quadratic Formula

Handbook 10.6, p. 37
x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Solve any equation of the form ax² + bx + c = 0 for its two roots.

xx
the roots, the values of x that make the equation equal zeroany consistent unit
aa
coefficient of the x² term (cannot be zero)any consistent unit
bb
coefficient of the x termany consistent unit
cc
constant termany consistent unit

Watch out: Move everything to one side so it equals zero before reading a, b and c, and keep their signs; if b² minus 4ac is negative there are no real roots.

Law of Sines

Handbook 10.6, p. 39
asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}

Solve a triangle that is not a right triangle when you know a side and its opposite angle plus one more side or angle.

aa
length of side a, opposite angle Aany consistent length unit
bb
length of side b, opposite angle Bany consistent length unit
cc
length of side c, opposite angle Cany consistent length unit
AA
interior angle opposite side a° or radians
BB
interior angle opposite side b° or radians
CC
interior angle opposite side c° or radians

Watch out: Each side must be paired with the angle across from it, and check that the calculator is in degree mode when the angles are in degrees.

Law of Cosines

Handbook 10.6, p. 39
c2=a2+b2−2abcos⁡Cc^2 = a^2 + b^2 - 2ab\cos C

Find the third side of a triangle from two sides and the angle between them, or find an angle when you know all three sides.

cc
the side opposite angle C, the one you are solving forany consistent length unit
aa
one of the two sides that form angle Cany consistent length unit
bb
the other side that forms angle Cany consistent length unit
CC
the angle between sides a and b° or radians

Watch out: C must be the angle between a and b (the included angle), not one of the other two angles.

Chain Rule

Handbook 10.6, p. 50
ddx[f(g(x))]=f′(g(x))⋅g′(x)\frac{d}{dx}[f(g(x))] = f'(g(x))\cdot g'(x)

Take the derivative of a function inside another function, like sin(3x²).

ff
the outer functionunitless
g(x)g(x)
the inner function, which is fed into funitless
xx
the variable you are differentiating with respect toany consistent unit
f′(g(x))f'(g(x))
derivative of the outer function, evaluated at the inner functionunitless
g′(x)g'(x)
derivative of the inner functionunitless

Watch out: Do not stop after differentiating the outer function; you still have to multiply by the derivative of the inside.

Integration by Parts

Handbook 10.6, p. 51
∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du

Integrate a product of two functions, like x times e^x or x times sin x.

uu
the part you choose to differentiate, ideally one that gets simplerunitless
dvdv
the part you choose to integrateunitless
dudu
the derivative of u times dxunitless
vv
the integral of dvunitless

Watch out: Pick u as the piece that gets simpler when differentiated (a power of x before e^x or sin x); the wrong pick makes the new integral harder.

Dot Product

Handbook 10.6, p. 61
A⃗⋅B⃗=∣A∣∣B∣cos⁡θ\vec{A}\cdot\vec{B} = |A||B|\cos\theta

Find the angle between two vectors, the projection of one onto the other, or the work done by a force.

A⃗\vec{A}
first vectorany consistent unit
B⃗\vec{B}
second vectorany consistent unit
∣A∣|A|
magnitude (length) of vector Asame unit as A
∣B∣|B|
magnitude (length) of vector Bsame unit as B
θ\theta
angle between the two vectors when placed tail to tail° or radians

Watch out: The result is a plain number, not a vector; with components it is simply ax·bx + ay·by + az·bz.

Cross Product

Handbook 10.6, p. 61
A⃗×B⃗=∣A∣∣B∣sin⁡θ n^\vec{A}\times\vec{B} = |A||B|\sin\theta\,\hat{n}

Find a vector perpendicular to two vectors, such as the moment of a force (r × F).

A⃗\vec{A}
first vectorany consistent unit
B⃗\vec{B}
second vectorany consistent unit
∣A∣|A|
magnitude (length) of vector Asame unit as A
∣B∣|B|
magnitude (length) of vector Bsame unit as B
θ\theta
angle between the two vectors when placed tail to tail° or radians
n^\hat{n}
unit vector perpendicular to the plane of A and B, direction set by the right-hand ruleunitless

Watch out: Order matters: A × B points the opposite way from B × A.

Spreadsheet order of operations

Not in the handbook: memorize it
=A1+A2*A3 → precedence: × before +\texttt{=A1+A2*A3}\ \rightarrow\ \text{precedence: } \times \text{ before } +

Predict what a spreadsheet cell formula returns when it mixes operations.

=\texttt{=}
starts a formula, so the cell shows the result instead of the textnone
A1\texttt{A1}
the value in column A, row 1whatever the cell holds
A2\texttt{A2}
the value in column A, row 2whatever the cell holds
A3\texttt{A3}
the value in column A, row 3whatever the cell holds
+\texttt{+}
addnone
*\texttt{*}
multiplynone

Watch out: =A1+A2*A3 multiplies A2 by A3 first and then adds A1; you need =(A1+A2)*A3 to add first.

Logical IF function

Not in the handbook: memorize it
IF(test, value if true, value if false)\texttt{IF(test, value if true, value if false)}

Make a spreadsheet cell return one value when a condition is true and another when it is false.

test\texttt{test}
a comparison that is either true or false, like A1>100true or false
value if true\texttt{value if true}
what the cell returns when the test is truewhatever the cell holds
value if false\texttt{value if false}
what the cell returns when the test is falsewhatever the cell holds

Watch out: In nested IFs the first test that is true wins, so check the order of the conditions.

Newton's Method (root-finding)

Handbook 10.6, p. 62
xj+1=xj−f(xj)f′(xj)x_{j+1} = x_j - \frac{f(x_j)}{f'(x_j)}

Find a root of f(x) = 0 numerically by improving a guess one step at a time.

xj+1x_{j+1}
the next, improved estimate of the rootsame unit as x
xjx_j
the current estimate of the rootsame unit as x
f(xj)f(x_j)
the function evaluated at the current estimatesame unit as f
f′(xj)f'(x_j)
the derivative of the function evaluated at the current estimatef units per x unit

Watch out: The starting guess must be near the root, and the method fails where the derivative is zero.

Probability & Statistics

Study guidePractice problems

Sample Mean

Handbook 10.6, p. 64
xˉ=∑xin\bar{x} = \frac{\sum x_i}{n}

Find the average of a set of measured values.

xˉ\bar{x}
sample mean, the average of the valuessame unit as the data
xix_i
each individual value in the samplesame unit as the data
nn
number of values in the sampleunitless (a count)

Sample Std Dev

Handbook 10.6, p. 64
s=∑(xi−xˉ)2n−1s = \sqrt{\frac{\sum(x_i - \bar{x})^2}{n-1}}

Measure how spread out a sample of values is around its mean.

ss
sample standard deviationsame unit as the data
xix_i
each individual value in the samplesame unit as the data
xˉ\bar{x}
sample meansame unit as the data
nn
number of values in the sampleunitless (a count)

Watch out: A sample divides by n minus 1; a whole population divides by N, so pick sx, not σx, on the calculator for a sample.

Binomial Distribution

Handbook 10.6, p. 67
P(X=k)=(nk)pk(1−p)n−kP(X=k) = \binom{n}{k}p^k(1-p)^{n-k}

Find the chance of exactly k successes in n independent tries, each with the same chance of success.

P(X=k)P(X=k)
probability of exactly k successesunitless, 0 to 1
nn
number of independent trialsunitless (a count)
kk
number of successes you are asking aboutunitless (a count)
pp
probability of success on one trial (1 minus p is the probability of failure)unitless, 0 to 1
(nk)\binom{n}{k}
number of ways to choose k successes out of n trials, n! divided by k!(n minus k)!unitless

Watch out: The formula gives exactly k; an "at least" or "at most" question needs a sum of terms, or 1 minus the complement.

Z-Score

Handbook 10.6, p. 68
z=x−μσz = \frac{x - \mu}{\sigma}

Convert a value from any normal distribution to the unit normal so you can read probabilities from the table.

zz
number of standard deviations the value sits above (or below, if negative) the meanunitless
xx
the value you are checkingsame unit as the data
μ\mu
population meansame unit as the data
σ\sigma
population standard deviationsame unit as the data

Watch out: The handbook table has four columns: F(x) is the area to the left, R(x) the area to the right, W(x) the area between minus x and x; read the one the question asks for.

Correlation Coefficient

Handbook 10.6, p. 71
r=∑(xi−xˉ)(yi−yˉ)∑(xi−xˉ)2∑(yi−yˉ)2r = \frac{\sum(x_i-\bar{x})(y_i-\bar{y})}{\sqrt{\sum(x_i-\bar{x})^2\sum(y_i-\bar{y})^2}}

Measure how closely two sets of paired data follow a straight line.

rr
correlation coefficient, from minus 1 (perfect falling line) through 0 (no linear trend) to plus 1 (perfect rising line)unitless
xix_i
each x value in the paired datasame unit as x
yiy_i
each y value paired with x_isame unit as y
xˉ\bar{x}
mean of the x valuessame unit as x
yˉ\bar{y}
mean of the y valuessame unit as y

Watch out: r is not the slope of the line, and the coefficient of determination R² is r squared.

Engineering Economics

Study guidePractice problems

Future Worth (Single Payment)

Handbook 10.6, p. 235
F=P(1+i)nF = P(1+i)^n

Find what one amount of money today grows to after n periods at interest rate i.

FF
future worth, the amount at the end of period ndollars
PP
present worth, the amount today (time zero)dollars
ii
interest rate per period, as a decimalunitless (per period)
nn
number of compounding periodsperiods (years, months)

Watch out: i and n must use the same period, so a monthly rate goes with a number of months.

Present Worth (Single Payment)

Handbook 10.6, p. 235
P=F(1+i)−nP = F(1+i)^{-n}

Find what one amount received in the future is worth today.

PP
present worth, the value today (time zero)dollars
FF
future amount, received at the end of period ndollars
ii
interest rate per period, as a decimalunitless (per period)
nn
number of compounding periodsperiods (years, months)

Watch out: i and n must use the same period, so a monthly rate goes with a number of months.

Capital Recovery

Handbook 10.6, p. 235
A=Pi(1+i)n(1+i)n−1A = P\frac{i(1+i)^n}{(1+i)^n - 1}

Turn an amount today into equal payments at the end of each period, like a loan payment.

AA
uniform amount paid at the end of each perioddollars per period
PP
present worth, the amount at time zerodollars
ii
interest rate per period, as a decimalunitless (per period)
nn
number of periods (payments)periods (years, months)

Watch out: The first payment A comes one period after P, not at time zero.

Benefit-Cost Ratio

Handbook 10.6, p. 237
B/C≥1B/C \geq 1

Decide whether a project is worth doing: it is justified when benefits are at least equal to costs.

BB
benefits of the projectdollars (present or annual worth)
CC
costs of the projectdollars (present or annual worth)

Watch out: B and C must be on the same basis (both present worth or both annual worth), and to choose between projects compare them incrementally, not by the biggest ratio.

Straight-Line Depreciation

Handbook 10.6, p. 236
Dj=Cost−SalvagenD_j = \frac{\text{Cost} - \text{Salvage}}{n}

Spread the loss in value of an asset evenly over its life.

DjD_j
depreciation in year j, the same every yeardollars per year
Cost\text{Cost}
initial cost of the assetdollars
Salvage\text{Salvage}
expected salvage value at the end of its lifedollars
nn
depreciable life of the assetyears

Watch out: Subtract the salvage value before dividing; book value in a later year is cost minus all depreciation taken so far.

Inflation-Adjusted Interest Rate

Handbook 10.6, p. 236
d=i+f+(i×f)d = i + f + (i \times f)

Combine the interest rate and the inflation rate into one rate for finding present worth of inflated cash flows.

dd
inflation-adjusted interest rate per periodunitless (per period)
ii
interest rate per period, without inflationunitless (per period)
ff
general inflation rate per periodunitless (per period)

Watch out: Multiply the decimals, not the percents: i = 5% and f = 3% give d = 0.05 + 0.03 + 0.0015 = 8.15%, not just 8%.

Internal Rate of Return (IRR)

Handbook 10.6, p. 236
PWbenefits−PWcosts=0PW_{benefits} - PW_{costs} = 0

Find the interest rate at which a project just breaks even, then compare it with the minimum acceptable rate (MARR).

PWbenefitsPW_{benefits}
present worth of all benefits (income) at the trial interest ratedollars
PWcostsPW_{costs}
present worth of all costs at the trial interest ratedollars

Watch out: The unknown is the interest rate, so you solve by trying rates (or reading the factor tables) until the two sides match; accept the project when that rate is at least the MARR.

Equilibrium Equations

Handbook 10.6, p. 95
∑Fx=0,∑Fy=0,∑M=0\sum F_x = 0,\quad \sum F_y = 0,\quad \sum M = 0

Find unknown forces and support reactions on a body that is not moving.

FxF_x
each force component in the x (horizontal) directionlbf, kips, N or kN
FyF_y
each force component in the y (vertical) directionlbf, kips, N or kN
MM
each moment about a point you choose, including couplesft·lbf, ft·kips, N·m or kN·m

Watch out: Take moments about a point where unknown forces act so they drop out, and keep one sign convention for every term.

Composite Centroid

Handbook 10.6, p. 96
xˉ=∑Aixi∑Ai\bar{x} = \frac{\sum A_i x_i}{\sum A_i}

Find the centroid of a shape built from simple pieces like rectangles, triangles and circles.

xˉ\bar{x}
x location of the centroid of the whole shape, from your reference axisin, ft, mm or m
AiA_i
area of each simple piecein², ft², mm² or m²
xix_i
x distance from the reference axis to the centroid of each piecein, ft, mm or m

Watch out: Treat holes and cut-outs as negative areas, and measure every x_i from the same reference axis.

Parallel Axis Theorem

Handbook 10.6, p. 96
Ix=Iˉx+Ad2I_x = \bar{I}_x + Ad^2

Move a moment of inertia from a centroidal axis to any parallel axis, usually to build up a composite section.

IxI_x
moment of inertia about the new (parallel) axisin⁴, ft⁴, mm⁴ or m⁴
Iˉx\bar{I}_x
moment of inertia about the axis through the shape's own centroidin⁴, ft⁴, mm⁴ or m⁴
AA
area of the shapein², ft², mm² or m²
dd
perpendicular distance between the centroidal axis and the new axisin, ft, mm or m

Watch out: You can only transfer from the centroidal axis; to go between two non-centroidal axes, first come back to the centroid.

Static Friction

Handbook 10.6, p. 97
F≤μsNF \leq \mu_s N

Check whether a body will slide, or find the force that starts it sliding.

FF
friction force along the contact surfacelbf or N
μs\mu_s
coefficient of static frictionunitless
NN
normal force, pressing the two surfaces together, perpendicular to the contactlbf or N

Watch out: F equals μs·N only when slip is about to happen; on a slope N is W cos θ, not the full weight W.

Moment of a Force

Handbook 10.6, p. 95
M=r×FM = r \times F

Find the turning effect of a force about a point.

MM
moment of the force about the pointft·lbf, ft·kips, N·m or kN·m
rr
position vector from the point to any point on the force's line of actionft, in, m or mm
FF
the forcelbf, kips, N or kN

Watch out: In the scalar form M = F·d, d is the perpendicular distance to the line of action, not the straight distance to where the force is applied.

Lever / Machine (mechanical advantage)

Not in the handbook: memorize it
Fout=Fin ainaoutF_{out} = F_{in}\,\frac{a_{in}}{a_{out}}

Find the force a lever or simple machine delivers, from moment balance about the pivot.

FoutF_{out}
force the lever delivers (output, or load)lbf or N
FinF_{in}
force applied to the lever (input, or effort)lbf or N
aina_{in}
moment arm of the input force, perpendicular distance from the pivotin, ft, mm or m
aouta_{out}
moment arm of the output force, perpendicular distance from the pivotin, ft, mm or m

Watch out: A longer input arm gives a bigger output force; flipping the ratio is the usual slip.

Constant Acceleration

Handbook 10.6, p. 105
v=v0+atv = v_0 + at

Find speed after a given time when acceleration does not change.

vv
velocity at time tft/s or m/s
v0v_0
initial velocity, at time zeroft/s or m/s
aa
constant acceleration (g for free fall)ft/s² or m/s²
tt
time elapseds

Watch out: Only valid when acceleration is constant; for free fall pick a direction as positive and give g its sign.

Displacement

Handbook 10.6, p. 105
s=s0+v0t+12at2s = s_0 + v_0 t + \frac{1}{2}at^2

Find position after a given time when acceleration does not change.

ss
position at time t, along the line of travelft or m
s0s_0
initial position, at time zeroft or m
v0v_0
initial velocity, at time zeroft/s or m/s
aa
constant acceleration (g for free fall)ft/s² or m/s²
tt
time elapseds

Watch out: Only valid when acceleration is constant; use g = 32.2 ft/s² or 9.81 m/s² with the sign of your chosen direction.

Velocity-Position

Handbook 10.6, p. 105
v2=v02+2a(s−s0)v^2 = v_0^2 + 2a(s - s_0)

Relate speed and distance when time is not given, like a braking or stopping distance.

vv
velocity at position sft/s or m/s
v0v_0
initial velocity, at position s_0ft/s or m/s
aa
constant acceleration (negative when slowing down)ft/s² or m/s²
ss
final positionft or m
s0s_0
initial positionft or m

Watch out: Convert mph or km/h to ft/s or m/s first (1 mph = 1.467 ft/s), and give deceleration a negative sign.

Newton's Second Law

Handbook 10.6, p. 106
∑F=ma\sum F = ma

Find the acceleration a set of forces gives a body, or the force needed for a given acceleration.

∑F\sum F
sum of all forces acting on the body, in the direction of motionlbf or N
mm
mass of the bodyslug (lbf·s²/ft) or kg
aa
acceleration of the bodyft/s² or m/s²

Watch out: In US units a weight in lbf is not a mass; divide by g = 32.2 ft/s² to get slugs.

Conservation of Energy

Handbook 10.6, p. 107
T1+V1=T2+V2T_1 + V_1 = T_2 + V_2

Relate speed and height (or spring stretch) at two points when no energy is lost to friction.

T1T_1
kinetic energy at state 1, one half m v²ft·lbf or J
V1V_1
potential energy at state 1, from height (mgh) and springs (one half k s²)ft·lbf or J
T2T_2
kinetic energy at state 2ft·lbf or J
V2V_2
potential energy at state 2ft·lbf or J

Watch out: With friction or other non-conservative forces, add the work term U1→2 (negative for friction) to the right side.

Conservation of Momentum

Handbook 10.6, p. 109
m1v1+m2v2=m1v1′+m2v2′m_1 v_1 + m_2 v_2 = m_1 v_1' + m_2 v_2'

Find velocities after two bodies collide, when no outside force acts during the impact.

m1m_1
mass of body 1slug or kg
m2m_2
mass of body 2slug or kg
v1v_1
velocity of body 1 just before impactft/s or m/s
v2v_2
velocity of body 2 just before impactft/s or m/s
v1′v_1'
velocity of body 1 just after impactft/s or m/s
v2′v_2'
velocity of body 2 just after impactft/s or m/s

Watch out: Velocities carry signs, so a body moving the other way is negative; momentum is conserved but kinetic energy is not, unless the impact is perfectly elastic (e = 1).

Natural Frequency

Handbook 10.6, p. 113
ωn=k/m\omega_n = \sqrt{k/m}

Find how fast an undamped spring and mass system vibrates on its own.

ωn\omega_n
undamped natural circular frequencyrad/s
kk
spring stiffness (spring constant)lbf/ft or N/m
mm
vibrating massslug or kg

Watch out: The answer is in rad/s; divide by 2π for cycles per second (Hz), and use mass, not weight, for m.

Mechanics of Materials

Study guidePractice problems

Axial Stress

Handbook 10.6, p. 131
σ=PA\sigma = \frac{P}{A}

Stress in a bar, rod or column loaded straight along its axis, in tension or compression.

σ\sigma
normal stress on the cross section (tension positive)psi or ksi, Pa or MPa
PP
axial load carried by the memberlb or kips, N or kN
AA
cross-sectional area perpendicular to the loadin² or mm², m²

Axial Deformation

Handbook 10.6, p. 131
δ=PLAE\delta = \frac{PL}{AE}

How much a bar stretches or shortens under an axial load while the material stays elastic.

δ\delta
change in length of the member (elongation or shortening)in. or mm
PP
axial load in the memberlb or kips, N or kN
LL
original length of the memberin. or mm
AA
cross-sectional areain² or mm²
EE
modulus of elasticity (Young's modulus) of the materialpsi or ksi, MPa or GPa

Watch out: Keep every length in the same unit as E: with E in ksi, use kips and inches, not feet.

Torsional Shear

Handbook 10.6, p. 134
τ=TcJ\tau = \frac{Tc}{J}

Maximum shear stress at the outer surface of a solid or thick-walled circular shaft carrying a torque.

τ\tau
shear stress at distance c from the center (the maximum when c is the outer radius)psi or ksi, MPa
TT
torque (twisting moment) on the shaftin·lb or kip·in, N·m
cc
radius from the shaft center to the point, usually the outer radiusin. or mm, m
JJ
polar moment of inertia of the cross section (πd⁴/32 for a solid shaft)in⁴ or mm⁴, m⁴

Watch out: c is the radius, not the diameter, and J is the polar moment (twice I for a circle), not I.

Flexural Stress

Handbook 10.6, p. 136
σ=McI\sigma = \frac{Mc}{I}

Maximum normal stress at the top or bottom fiber of a beam under a bending moment.

σ\sigma
bending (normal) stress at the extreme fiberpsi or ksi, MPa
MM
bending moment at the sectionin·lb or kip·in, N·m or kN·m
cc
distance from the neutral axis to the outermost fiberin. or mm
II
moment of inertia of the cross section about the neutral axisin⁴ or mm⁴

Watch out: Moments are often given in kip·ft; multiply by 12 to get kip·in before dividing by I in in⁴.

Transverse Shear

Handbook 10.6, p. 136
τ=VQIb\tau = \frac{VQ}{Ib}

Shear stress at a given height inside a beam cross section caused by the internal shear force.

τ\tau
transverse shear stress at the level you are checkingpsi or ksi, MPa
VV
internal shear force at the sectionlb or kips, N or kN
QQ
first moment of the area above (or below) that level about the neutral axis, area times distance to its centroidin³ or mm³
II
moment of inertia of the whole cross section about the neutral axisin⁴ or mm⁴
bb
width of the cross section at the level you are checkingin. or mm

Watch out: b is the width at the cut, so in an I-beam web use the web thickness, not the flange width.

Simply Supported Beam (midpoint load)

Handbook 10.6, p. 140
δmax=PL348EI\delta_{max} = \frac{PL^3}{48EI}

Maximum deflection, at midspan, of a simply supported beam with one point load at the middle.

δmax\delta_{max}
maximum deflection, at midspanin. or mm
PP
concentrated load at midspanlb or kips, N or kN
LL
span length between supportsin. or mm
EE
modulus of elasticity of the beam materialpsi or ksi, MPa
II
moment of inertia of the beam cross sectionin⁴ or mm⁴

Watch out: L is cubed, so leaving the span in feet while E and I are in inches makes the answer 1,728 times too small.

Principal Stresses

Handbook 10.6, p. 132
σ1,2=σx+σy2±(σx−σy2)2+τxy2\sigma_{1,2} = \frac{\sigma_x+\sigma_y}{2}\pm\sqrt{\left(\frac{\sigma_x-\sigma_y}{2}\right)^2+\tau_{xy}^2}

Largest and smallest normal stresses at a point under 2D (plane) stress, on planes where the shear is zero.

σ1,2\sigma_{1,2}
the two in-plane principal stresses (plus sign gives the larger)psi or ksi, MPa
σx\sigma_x
normal stress on the face perpendicular to x (tension positive)psi or ksi, MPa
σy\sigma_y
normal stress on the face perpendicular to y (tension positive)psi or ksi, MPa
τxy\tau_{xy}
shear stress on the x and y facespsi or ksi, MPa

Watch out: Enter compression as a negative number; the square root term alone is the maximum in-plane shear stress.

Euler's Buckling Load

Handbook 10.6, p. 137
Pcr=π2EI(KL)2P_{cr} = \frac{\pi^2 EI}{(KL)^2}

Axial load at which a long, slender column buckles elastically.

PcrP_{cr}
critical (buckling) axial loadlb or kips, N or kN
EE
modulus of elasticity of the column materialpsi or ksi, MPa
II
moment of inertia about the axis the column buckles around, normally the weak axisin⁴ or mm⁴
KK
effective-length factor for the end supports (pinned-pinned 1.0, fixed-pinned 0.7, fixed-fixed 0.5, fixed-free 2.0)unitless
LL
unbraced length of the columnin. or mm

Watch out: Use the smaller moment of inertia unless the weak axis is braced, and K = 2.0 for a flagpole (fixed-free) column.

Transformed (Composite) Section

Handbook 10.6, p. 137
σ1=nMyIT,  n=E1E2\sigma_1 = \frac{nMy}{I_T}, \; n = \frac{E_1}{E_2}

Bending stress in a beam made of two materials, such as steel plates on wood, after converting it to one material.

σ1\sigma_1
bending stress in the stiffer Material 1psi or ksi, MPa
nn
modular ratio, E₁ divided by E₂unitless
MM
bending moment at the sectionin·lb or kip·in, N·m
yy
distance from the neutral axis of the transformed section to the fiberin. or mm
ITI_T
moment of inertia of the transformed sectionin⁴ or mm⁴
E1E_1
modulus of elasticity of Material 1 (the stiffer one)psi or ksi, MPa
E2E_2
modulus of elasticity of Material 2psi or ksi, MPa

Watch out: Find the neutral axis on the transformed section first, and multiply by n only for stress in the stiffer material.

Plastic Moment (Z = plastic section modulus)

Handbook 10.6, p. 287
Mp=FyZM_p = F_y Z

Bending strength of a compact steel beam when the whole section has yielded (the yielding limit state, Mn = Mp).

MpM_p
plastic moment, the moment when the entire cross section has yieldedkip·in or kip·ft, kN·m
FyF_y
specified minimum yield stress of the steel (50 ksi for A992)ksi or MPa
ZZ
plastic section modulus about the bending axis (Zx in the AISC tables)in³ or mm³

Watch out: Use Z, not the elastic section modulus S; S times Fy is only the first-yield moment, about 10 to 15% lower for a W shape.

Engineering Stress

Handbook 10.6, p. 122
σ=FA0\sigma = \frac{F}{A_0}

Stress from a tension test, using the specimen area before it was loaded.

σ\sigma
engineering stresspsi or ksi, MPa
FF
applied forcelb or kips, N or kN
A0A_0
original (initial) cross-sectional area of the specimenin² or mm²

Watch out: Use the original area; dividing by the shrunken (necked) area gives true stress, which is larger.

Hooke's Law

Handbook 10.6, p. 122
σ=Eε\sigma = E\varepsilon

Link stress and strain while the material is still elastic (below the proportional limit).

σ\sigma
normal stresspsi or ksi, MPa
EE
modulus of elasticity (Young's modulus), the slope of the straight part of the stress-strain curvepsi or ksi, MPa or GPa
ε\varepsilon
normal strain, change in length divided by original lengthunitless (in./in. or mm/mm)

Watch out: Strain is often given in percent or microstrain; convert to a plain decimal before multiplying by E.

BHN–Tensile Strength

Handbook 10.6, p. 123
TS (MPa)≈3.45×BHNTS \text{ (MPa)} \approx 3.45 \times BHN

Quick estimate of the tensile strength of a plain carbon steel from its Brinell hardness number.

TSTS
ultimate tensile strength of the steelMPa (the US form is TS in psi ≈ 500 × BHN)
BHNBHN
Brinell hardness number from the indentation testunitless (a hardness index)

Watch out: The factor near 3.5 gives MPa; for psi the handbook uses 500 × BHN, and both apply to plain carbon steels only.

Fracture Toughness

Handbook 10.6, p. 123
KIC=YσπaK_{IC} = Y\sigma\sqrt{\pi a}

Check whether a crack of a given size will run (fast fracture) at a given applied stress in a brittle material.

KICK_{IC}
fracture toughness, the critical stress intensity at which the crack propagatesMPa·√m or ksi·√in.
YY
geometry factor (1.1 for an exterior edge crack, 1.0 for an interior crack)unitless
σ\sigma
applied engineering stressMPa or ksi
aa
crack length for an edge crack, or half the total length for an interior crackm or in.

Watch out: An interior crack of total length 2a uses only a, and a must be in meters (or inches) to match the units of K.

Thermal Expansion

Handbook 10.6, p. 127
ΔL=αLΔT\Delta L = \alpha L \Delta T

Change in length of a member that is free to move when its temperature changes.

ΔL\Delta L
change in lengthin. or mm
α\alpha
coefficient of thermal expansion1/°F or 1/°C
LL
original lengthin. or mm
ΔT\Delta T
change in temperature (final minus initial)°F or °C

Watch out: Match α to the temperature unit: a value per °C used with a change in °F is off by a factor of 1.8.

Water-Cement Ratio

Handbook 10.6, p. 126
W/C=weight of waterweight of cementW/C = \frac{\text{weight of water}}{\text{weight of cement}}

The main factor that controls concrete strength: lower W/C gives stronger, more durable concrete.

W/CW/C
weight of mixing water divided by weight of cement in the same batchunitless

Watch out: It is a ratio by weight, not volume; adding water without adding cement raises W/C and lowers strength.

Rule of Mixtures (Modulus)

Handbook 10.6, p. 124
Ec=f1E1+f2E2E_c = f_1 E_1 + f_2 E_2

Stiffness of a fiber composite loaded parallel to long, aligned fibers.

EcE_c
Young's modulus of the compositepsi or ksi, GPa
f1f_1
volume fraction of material 1unitless (0 to 1)
E1E_1
Young's modulus of material 1psi or ksi, GPa
f2f_2
volume fraction of material 2 (f₁ + f₂ = 1)unitless (0 to 1)
E2E_2
Young's modulus of material 2psi or ksi, GPa

Watch out: Use volume fractions, not weight fractions; this is the upper bound, and loading across the fibers uses the inverse rule (1/E_c = Σ f/E).

Aggregate Bulk Specific Gravity

Not in the handbook: memorize it
Gsb=AB−CG_{sb} = \frac{A}{B - C}

Bulk (oven-dry) specific gravity of coarse aggregate from the soaking test (ASTM C127), used in concrete and asphalt mix design.

GsbG_{sb}
bulk specific gravity of the aggregate on an oven-dry basisunitless
AA
mass of the oven-dry sample in airg or lb
BB
mass of the saturated surface-dry (SSD) sample in airg or lb
CC
mass of the saturated sample weighed submerged in waterg or lb

Watch out: Putting B on top gives the SSD specific gravity and A/(A minus C) gives the apparent one, so check which numerator the question wants.

Aggregate Absorption (%)

Not in the handbook: memorize it
Absorption=WSSD−WODWOD×100\text{Absorption} = \frac{W_{SSD} - W_{OD}}{W_{OD}} \times 100

How much water an aggregate soaks into its pores, used to correct mix water in concrete.

Absorption\text{Absorption}
water held in the pores at SSD, as a percent of the dry masspercent
WSSDW_{SSD}
weight of the sample in the saturated surface-dry conditiong or lb
WODW_{OD}
weight of the oven-dry sampleg or lb

Watch out: Divide by the oven-dry weight, not the SSD weight.

Asphalt Air Voids (VTM)

Not in the handbook: memorize it
Va=100Gmm−GmbGmmV_a = 100\frac{G_{mm} - G_{mb}}{G_{mm}}

Percent of a compacted asphalt mix volume that is air, the main Superpave design check (target about 4%).

VaV_a
air voids in the compacted mix (voids in total mix)percent
GmmG_{mm}
theoretical maximum specific gravity of the loose mix with no air (Rice value)unitless
GmbG_{mb}
bulk specific gravity of the compacted mix specimenunitless

Watch out: G_mm is always the larger number; swapping the two gives a negative air void value.

Voids Filled with Asphalt

Not in the handbook: memorize it
VFA=100VMA−VaVMAVFA = 100\frac{VMA - V_a}{VMA}

Percent of the space between aggregate particles (VMA) that is filled with asphalt binder rather than air.

VFAVFA
voids filled with asphaltpercent
VMAVMA
voids in the mineral aggregate, the space between aggregate particles (air plus effective binder)percent of total mix volume
VaV_a
air voids in the compacted mixpercent of total mix volume

Watch out: Enter VMA and V_a as percents (16, not 0.16) so the factor of 100 gives a percent.

Wood Moisture Content

Not in the handbook: memorize it
MC%=Wwet−WODWOD×100MC\% = \frac{W_{wet} - W_{OD}}{W_{OD}} \times 100

Water in a piece of wood as a percent of its oven-dry weight, which controls its strength and shrinkage.

MC%MC\%
moisture content on an oven-dry basispercent
WwetW_{wet}
weight of the wood as tested, with its moistureg or lb
WODW_{OD}
weight of the same wood after oven dryingg or lb

Watch out: Divide by the oven-dry weight, so green wood can show a moisture content above 100%.

Specific Weight

Handbook 10.6, p. 181
γ=ρg\gamma = \rho g

Convert a fluid density into weight per unit volume, the quantity used in pressure and force problems.

γ\gamma
specific weight, weight per unit volume (water is 62.4 lbf/ft³ or 9.81 kN/m³)lbf/ft³ or N/m³
ρ\rho
density, mass per unit volume (water is 1.94 slug/ft³ or 1,000 kg/m³)slug/ft³ or kg/m³
gg
acceleration of gravity32.2 ft/s² or 9.81 m/s²

Watch out: In US units use density in slug/ft³; 62.4 is the specific weight of water, not its density in slugs.

Newton's Law of Viscosity

Handbook 10.6, p. 181
τ=μdvdy\tau = \mu \frac{dv}{dy}

Shear stress in a Newtonian fluid layer from its velocity gradient, for example oil between a moving plate and a fixed one.

τ\tau
shear stress in the fluidlbf/ft² or Pa (N/m²)
μ\mu
absolute (dynamic) viscositylbf·s/ft² or Pa·s (N·s/m²)
dvdy\frac{dv}{dy}
velocity gradient, change in velocity per distance normal to the wall1/s

Watch out: For a thin film with a straight-line profile, dv/dy is the plate speed divided by the film thickness, and use μ, not the kinematic viscosity ν.

Hydrostatic Pressure

Handbook 10.6, p. 182
P2−P1=γhP_2 - P_1 = \gamma h

Pressure change between two points in a fluid at rest that differ in depth.

P2P_2
pressure at the lower pointpsf or psi, Pa or kPa
P1P_1
pressure at the upper pointpsf or psi, Pa or kPa
γ\gamma
specific weight of the fluidlbf/ft³ or N/m³
hh
vertical depth of point 2 below point 1ft or m

Watch out: γh in lbf/ft³ times ft gives psf; divide by 144 for psi.

Hydrostatic Force

Handbook 10.6, p. 184
FR=γhCAF_R = \gamma h_C A

Total water force on a flat submerged surface such as a gate or wall (atmospheric pressure on both sides).

FRF_R
resultant hydrostatic force on the surfacelbf or kips, N or kN
γ\gamma
specific weight of the fluidlbf/ft³ or N/m³
hCh_C
vertical depth from the free surface to the centroid of the submerged areaft or m
AA
area of the submerged surfaceft² or m²

Watch out: h_C is the vertical depth, not the slant distance along an inclined gate, and the force acts at the center of pressure, below the centroid.

Continuity

Handbook 10.6, p. 185
A1v1=A2v2A_1 v_1 = A_2 v_2

Velocity at one section of a pipe or channel from the velocity at another, for steady incompressible flow.

A1A_1
flow area at section 1ft² or m²
v1v_1
average velocity at section 1ft/s or m/s
A2A_2
flow area at section 2ft² or m²
v2v_2
average velocity at section 2ft/s or m/s

Watch out: Area goes with diameter squared, so halving a pipe diameter makes the velocity four times larger, not two.

Bernoulli's Equation

Handbook 10.6, p. 185
P1γ+v122g+z1=P2γ+v222g+z2\frac{P_1}{\gamma} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{\gamma} + \frac{v_2^2}{2g} + z_2

Trade pressure, velocity and elevation head between two points along a flow with no friction loss and no pump or turbine.

P1P_1
pressure at point 1lbf/ft² or Pa
P2P_2
pressure at point 2lbf/ft² or Pa
γ\gamma
specific weight of the fluidlbf/ft³ or N/m³
v1v_1
average velocity at point 1ft/s or m/s
v2v_2
average velocity at point 2ft/s or m/s
gg
acceleration of gravity32.2 ft/s² or 9.81 m/s²
z1z_1
elevation of point 1 above a chosen datumft or m
z2z_2
elevation of point 2 above the same datumft or m

Watch out: Use the same pressure basis at both points (a free surface or open jet is 0 gauge), and add head loss or pump head when the problem has them.

Reynolds Number

Handbook 10.6, p. 186
Re=ρvDμ=vDνRe = \frac{\rho v D}{\mu} = \frac{vD}{\nu}

Tell whether pipe flow is laminar or turbulent, and read the Moody chart.

ReRe
Reynolds number, inertial forces over viscous forces (laminar below 2,100, turbulent above 10,000 in a pipe)unitless
ρ\rho
fluid densityslug/ft³ or kg/m³
vv
average flow velocityft/s or m/s
DD
pipe diameter, or characteristic lengthft or m
μ\mu
dynamic viscositylbf·s/ft² or Pa·s
ν\nu
kinematic viscosity, μ divided by ρft²/s or m²/s

Watch out: Use ρvD/μ with dynamic viscosity or vD/ν with kinematic viscosity, never mix the two, and convert D from inches to feet.

Darcy-Weisbach

Handbook 10.6, p. 187
hf=fLDv22gh_f = f\frac{L}{D}\frac{v^2}{2g}

Friction head loss along a straight pipe for any fluid and any flow regime.

hfh_f
head loss due to frictionft or m
ff
Darcy (Moody) friction factor, from the Moody chart using Re and ε/Dunitless
LL
length of pipeft or m
DD
inside diameter of the pipeft or m
vv
average velocity in the pipeft/s or m/s
gg
acceleration of gravity32.2 ft/s² or 9.81 m/s²

Watch out: f here is the Darcy factor, four times the Fanning factor; for laminar flow f = 64/Re.

Momentum Equation

Handbook 10.6, p. 191
ΣF=ρQ(v2−v1)\Sigma F = \rho Q(v_2 - v_1)

Force needed to change the speed or direction of a flowing stream, such as at a pipe bend, nozzle or jet hitting a plate.

ΣF\Sigma F
sum of external forces on the fluid in the control volume, in one directionlbf or N
ρ\rho
fluid densityslug/ft³ or kg/m³
QQ
volumetric flow rateft³/s or m³/s
v2v_2
velocity component leaving the control volume, in the direction of the forceft/s or m/s
v1v_1
velocity component entering the control volume, in the same directionft/s or m/s

Watch out: Write it separately for x and y with signed components; it gives the force on the fluid, and the force on the bend is equal and opposite.

Traverse Lat/Dep

Handbook 10.6, p. 315
Lat=Lcos⁡θ,Dep=Lsin⁡θ\text{Lat} = L\cos\theta, \quad \text{Dep} = L\sin\theta

Break a traverse course into its north-south (latitude) and east-west (departure) components.

Lat\text{Lat}
latitude, the north-south component of the course (north positive)ft or m
Dep\text{Dep}
departure, the east-west component of the course (east positive)ft or m
LL
horizontal length of the courseft or m
θ\theta
direction of the course measured from north (bearing angle or azimuth)degrees

Watch out: The angle is measured from north, so latitude uses cosine; with bearings, set the signs from the quadrant (S is negative latitude, W is negative departure).

Coordinate Area

Handbook 10.6, p. 316
A=12∣∑(xiyi+1−xi+1yi)∣A = \frac{1}{2}|\sum(x_i y_{i+1} - x_{i+1} y_i)|

Area enclosed by a closed traverse when you know the coordinates of every corner.

AA
area enclosed by the polygonft² or m²
xix_i
x coordinate (easting) of corner ift or m
yiy_i
y coordinate (northing) of corner ift or m
xi+1x_{i+1}
x coordinate of the next corner around the polygonft or m
yi+1y_{i+1}
y coordinate of the next corner around the polygonft or m

Watch out: List the corners in order around the shape and close back to the first one; divide square feet by 43,560 for acres.

Average End Area

Handbook 10.6, p. 315
V=L2(A1+A2)V = \frac{L}{2}(A_1 + A_2)

Earthwork volume between two cross sections a known distance apart.

VV
volume of earth between the two sectionsft³ or m³
LL
distance between the two cross sectionsft or m
A1A_1
cross-sectional area at the first stationft² or m²
A2A_2
cross-sectional area at the second stationft² or m²

Watch out: Earthwork answers are usually in cubic yards, so divide cubic feet by 27.

Prismoidal Formula

Handbook 10.6, p. 315
V=L6(A1+4Am+A2)V = \frac{L}{6}(A_1 + 4A_m + A_2)

More accurate earthwork volume between two cross sections when the area at the midpoint is also known.

VV
volume of earth between the two end sectionsft³ or m³
LL
distance between the two end sectionsft or m
A1A_1
cross-sectional area at the first endft² or m²
AmA_m
cross-sectional area at the mid-section, halfway between the endsft² or m²
A2A_2
cross-sectional area at the second endft² or m²

Watch out: A_m is the area of the actual middle section (from averaged dimensions), not the average of A_1 and A_2.

Horizontal Curve Tangent

Handbook 10.6, p. 308
T=Rtan⁡I2T = R\tan\frac{I}{2}

Distance from the PC (or PT) to the PI of a simple circular horizontal curve.

TT
tangent distance, from the PC or PT to the PIft or m
RR
radius of the curveft or m
II
intersection (deflection) angle between the two tangents, also written Δdegrees

Watch out: Use half the intersection angle; stationing to the PT runs along the curve (PC plus L), not along the tangents.

Degree of Curve

Handbook 10.6, p. 308
D=5,729.58RD = \frac{5{,}729.58}{R}

Convert between curve radius and degree of curve (arc definition) in US highway work.

DD
degree of curve, the central angle that subtends a 100 ft arcdegrees
RR
radius of the curveft

Watch out: The constant 5,729.58 only works with R in feet and a 100 ft arc; it does not apply in meters.

Vertical Curve Elevation

Handbook 10.6, p. 307
Y=YPVC+g1x+g2−g12Lx2Y = Y_{PVC} + g_1 x + \frac{g_2 - g_1}{2L}x^2

Elevation of any point on a parabolic vertical curve at a horizontal distance x from the PVC.

YY
elevation of the curve at distance xft or m
YPVCY_{PVC}
elevation of the PVC, the start of the curveft or m
g1g_1
grade of the back (entering) tangent, percent divided by 100ft/ft (decimal)
g2g_2
grade of the forward (leaving) tangent, percent divided by 100ft/ft (decimal)
LL
horizontal length of the curve, PVC to PVTft or m
xx
horizontal distance from the PVC to the pointft or m

Watch out: Grades as decimals need L and x in feet; if you keep grades in percent, L and x must be in stations (100 ft).

Inverse Computation (distance & azimuth)

Not in the handbook: memorize it
L=ΔE2+ΔN2,  Az=tan⁡−1 ⁣ΔEΔNL = \sqrt{\Delta E^2 + \Delta N^2}, \; Az = \tan^{-1}\!\frac{\Delta E}{\Delta N}

Distance and direction between two points when you know their coordinates.

LL
horizontal distance between the two pointsft or m
ΔE\Delta E
change in easting, second point minus firstft or m
ΔN\Delta N
change in northing, second point minus firstft or m
AzAz
azimuth from the first point to the second, clockwise from northdegrees (0 to 360)

Watch out: A calculator arctangent only returns -90° to 90°; use the signs of ΔE and ΔN to put the azimuth in the right quadrant.

Water Resources & Env.

Study guidePractice problems

Manning's Equation

Handbook 10.6, p. 303
Q=KnARH2/3S1/2Q = \frac{K}{n}AR_H^{2/3}S^{1/2}

Flow in an open channel or a pipe flowing partly full, when you know the roughness n.

QQ
discharge (flow rate)ft³/s or m³/s
KK
unit constant, 1.486 in US units and 1.0 in SIunitless
nn
Manning roughness coefficient of the channel or pipe surfaceunitless
AA
cross-sectional area of flowft² or m²
RHR_H
hydraulic radius, flow area divided by wetted perimeterft or m
SS
slope of the energy grade line, equal to the channel bed slope in uniform flowft/ft or m/m

Watch out: K is 1.486 in US units and 1.0 in SI. Forgetting it gives an answer about 33% low.

Hazen-Williams

Handbook 10.6, p. 303
v=k1CRH0.63Sv0.54v = k_1 C R_H^{0.63} S_v^{0.54}

Velocity of water in a pressure pipe (water distribution), using the Hazen-Williams roughness C.

vv
average velocity in the pipeft/s or m/s
k1k_1
unit constant, 1.318 in US units and 0.849 in SIunitless
CC
Hazen-Williams roughness coefficient (higher is smoother)unitless
RHR_H
hydraulic radius, D/4 for a pipe flowing fullft or m
SvS_v
slope of the energy grade line, head loss divided by pipe lengthft/ft or m/m

Watch out: For a full circular pipe R_H is D/4, not D/2; using the radius makes the velocity about 55% too high.

Specific Energy

Handbook 10.6, p. 301
E=αv22g+yE = \frac{\alpha v^2}{2g} + y

Energy of open channel flow measured from the channel bottom, used for critical depth and alternate depth problems.

EE
specific energy, depth plus velocity head above the channel bottomft or m
α\alpha
kinetic energy correction factor, usually 1.0unitless
vv
average velocity of flowft/s or m/s
gg
acceleration of gravity32.2 ft/s² or 9.81 m/s²
yy
depth of flowft or m

Watch out: Specific energy is measured from the channel bottom, so there is no elevation term; the same E can occur at two depths (alternate depths).

Critical Depth (Rectangular)

Handbook 10.6, p. 302
yc=(q2/g)1/3y_c = (q^2/g)^{1/3}

Depth at which flow in a rectangular channel is critical (minimum specific energy, Froude number of 1).

ycy_c
critical depthft or m
qq
unit discharge, flow divided by channel width (Q/B)ft²/s or m²/s
gg
acceleration of gravity32.2 ft/s² or 9.81 m/s²

Watch out: Use the flow per foot of width q, not the total flow Q.

Rational Method

Handbook 10.6, p. 296
Q=CIAQ = CIA

Peak runoff rate from a small watershed for a storm whose duration equals the time of concentration.

QQ
peak dischargecfs (ft³/s)
CC
runoff coefficient, the fraction of rainfall that runs off (area-weighted if mixed land use)unitless (0 to 1)
II
rainfall intensity for a duration equal to the time of concentrationin./hr
AA
drainage (watershed) areaacres

Watch out: The formula only gives cfs with I in in./hr and A in acres; read I from the IDF curve at the time of concentration.

SCS Runoff Equation

Handbook 10.6, p. 296
Q=(P−0.2S)2P+0.8SQ = \frac{(P - 0.2S)^2}{P + 0.8S}

Depth of direct runoff from a storm rainfall depth, using the NRCS (SCS) curve number method.

QQ
runoff depth over the watershedin.
PP
rainfall (precipitation) depthin.
SS
maximum basin retention, S = 1,000/CN minus 10in.

Watch out: Q here is a depth in inches, not a flow rate, and runoff is zero when P is less than 0.2S.

Darcy's Law

Handbook 10.6, p. 298
Q=−KAdhdxQ = -KA\frac{dh}{dx}

Flow of groundwater through soil or an aquifer driven by a difference in head.

QQ
flow rate through the soilft³/s or m³/s
KK
hydraulic conductivity (coefficient of permeability)ft/s or m/s
AA
total (gross) cross-sectional area of flow, soil plus voidsft² or m²
dhdx\frac{dh}{dx}
hydraulic gradient, change in head per distance along the flowunitless (ft/ft or m/m)

Watch out: Q divided by A is the Darcy velocity; the actual seepage velocity is that divided by the effective porosity.

Dupuit's Formula

Handbook 10.6, p. 299
Q=πK(h22−h12)ln⁡(r2/r1)Q = \frac{\pi K(h_2^2 - h_1^2)}{\ln(r_2/r_1)}

Steady pumping rate from a well in an unconfined (water table) aquifer.

QQ
pumping rate from the wellft³/s or m³/s
KK
hydraulic conductivity of the aquiferft/s or m/s
h2h_2
height of the water table above the aquifer bottom at radius r₂ft or m
h1h_1
height of the water table above the aquifer bottom at radius r₁ (at the well if r₁ is the well radius)ft or m
r2r_2
distance from the well center to the farther observation pointft or m
r1r_1
distance from the well center to the nearer point, or the well radiusft or m

Watch out: h is height above the aquifer bottom, not drawdown, and the heads are squared; do not mix it up with the confined (Thiem) form.

Thiem Equation

Handbook 10.6, p. 299
Q=2πT(h2−h1)ln⁡(r2/r1)Q = \frac{2\pi T(h_2 - h_1)}{\ln(r_2/r_1)}

Steady pumping rate from a well in a confined aquifer.

QQ
pumping rate from the wellft³/s or m³/s
TT
transmissivity, hydraulic conductivity times aquifer thickness (Kb)ft²/s or m²/s
h2h_2
piezometric head above the aquifer bottom at radius r₂ft or m
h1h_1
piezometric head above the aquifer bottom at radius r₁ft or m
r2r_2
distance from the well center to the farther pointft or m
r1r_1
distance from the well center to the nearer pointft or m

Watch out: If you are given K instead of T, multiply by the aquifer thickness b; the heads here are not squared.

BOD Decay

Handbook 10.6, p. 327
BODt=L0(1−e−kt)BOD_t = L_0(1-e^{-kt})

BOD exerted after t days from the ultimate BOD and the decay rate, or the reverse.

BODtBOD_t
BOD exerted (oxygen used) by time tmg/L
L0L_0
ultimate BOD, the total oxygen demand of the wastemg/L
kk
BOD decay rate constant, base e1/day
tt
time since the test starteddays

Watch out: k must be the base-e rate; a base-10 rate must be multiplied by 2.303 first.

Clarifier Overflow Rate

Handbook 10.6, p. 345
vo=Q/Asurfacev_o = Q/A_{surface}

Size a settling tank (clarifier): the overflow rate equals the settling velocity of the smallest particle removed 100%.

vov_o
overflow rate (hydraulic loading rate), also the critical settling velocitygpd/ft² or m³/(m²·d)
QQ
flow into the clarifiergpd or m³/d
AsurfaceA_{surface}
surface (plan view) area of the tankft² or m²

Watch out: Use the surface area seen from above, not the cross-sectional area; tank depth does not enter the overflow rate.

Filtration Rate

Handbook 10.6, p. 347
vs=Q/Aplanv_s = Q/A_{plan}

Loading rate on a granular filter, the flow divided by the filter bed area.

vsv_s
filtration rate, the empty-bed approach velocitygpm/ft² or m/h
QQ
flow through the filtergpm or m³/h
AplanA_{plan}
plan (top view) area of the filter bedft² or m²

Watch out: Here v_s is a filtration rate, not a particle settling velocity; divide by the area of the filters in service.

Disinfection CT

Handbook 10.6, p. 352
CT=C×t10CT = C \times t_{10}

Disinfection dose achieved in a contact basin, compared with the CT required for a given log inactivation.

CTCT
calculated CT value, concentration times contact timemg·min/L
CC
residual disinfectant concentration at peak hourly flowmg/L
t10t_{10}
time for 10% of the water to pass through the basin, about the residence time times the baffling factormin

Watch out: Use t₁₀, not the full hydraulic residence time; multiply V/Q by the baffling factor first.

Pump Power Equation

Handbook 10.6, p. 197
W˙=γQH/η\dot W = \gamma Q H / \eta

Power a pump needs (input power) to deliver a flow against a given head.

W˙\dot W
power input to the pump (brake power, or purchased power if η includes the motor)ft·lbf/s or hp, W or kW
γ\gamma
specific weight of the fluidlbf/ft³ or N/m³
QQ
flow rateft³/s or m³/s
HH
total head added by the pumpft or m
η\eta
efficiency as a decimal (pump alone, or pump times motor for total)unitless (0 to 1)

Watch out: Divide ft·lbf/s by 550 for horsepower, and divide by efficiency, since the input power is larger than the water power.

NPSH Available

Handbook 10.6, p. 196
NPSHA=Hpa+Hs−∑hL−HvpNPSH_A = H_{pa} + H_s - \sum h_L - H_{vp}

Check a pump against cavitation: the NPSH available must exceed the NPSH required by the pump.

NPSHANPSH_A
net positive suction head available at the pump inletft or m
HpaH_{pa}
atmospheric pressure head on the liquid surface in the sumpft or m
HsH_s
static suction head, height of the liquid surface above the pump impeller centerline (negative if below)ft or m
∑hL\sum h_L
total friction losses in the suction lineft or m
HvpH_{vp}
vapor pressure head of the liquid at the operating temperatureft or m

Watch out: When the water level is below the pump (suction lift), H_s is negative; convert every pressure to head of the liquid being pumped.

Total Hardness as CaCO₃

Not in the handbook: memorize it
Hardness as CaCO3=∑Ci50EWi\text{Hardness as CaCO}_3 = \sum C_i \tfrac{50}{EW_i}

Express the total hardness of a water as mg/L of calcium carbonate from the measured hardness ions.

Hardness as CaCO3\text{Hardness as CaCO}_3
total hardness expressed as an equivalent amount of calcium carbonatemg/L as CaCO₃
CiC_i
measured concentration of each hardness ion (mainly Ca²⁺ and Mg²⁺)mg/L
EWiEW_i
equivalent weight of that ion, molecular weight divided by its charge (Ca²⁺ 20.0, Mg²⁺ 12.2); 50 is the equivalent weight of CaCO₃mg/meq (g/eq)

Watch out: Only multivalent cations count as hardness, so leave out Na⁺ and K⁺, and divide the molecular weight by the charge to get the equivalent weight.

Structural Engineering

Study guidePractice problems

Truss Stability/Determinacy

Handbook 10.6, p. 277
r+m≥2jr + m \geq 2j

Check whether a plane truss is unstable, statically determinate, or indeterminate before you try to solve it.

rr
number of independent support reaction componentsunitless (a count)
mm
number of members (bars)unitless (a count)
jj
number of joints, including the support jointsunitless (a count)

Watch out: Passing the count is not enough: a truss with m + r ≥ 2j can still be unstable if its members or supports are badly arranged (for example, all reactions parallel).

Deflection (Unit-Load Method)

Handbook 10.6, pp. 274–275
δ=∑nNLAE,δ=∫mMEI dx\delta = \sum \frac{nNL}{AE}, \quad \delta = \int \frac{mM}{EI}\,dx

Find the deflection at one point of a truss (first form) or a beam or frame (second form) by applying a unit load at that point in the direction you want.

δ\delta
displacement at the point and in the direction of the unit load (positive in the direction of the unit load)in. or mm
nn
force in a truss member caused by the unit load alone (tension positive)unitless (force per unit of applied load)
NN
force in the same truss member caused by the real loads (tension positive)kips or kN
LL
length of the truss memberin. or mm
AA
cross-sectional area of the truss memberin² or mm²
EE
modulus of elasticity of the member materialksi or MPa
mm
bending moment equation along a beam or frame member caused by the unit load aloneft or m (moment per unit of applied load)
MM
bending moment equation along the same member caused by the real loadskip·ft or kN·m
II
moment of inertia of the member cross sectionin⁴ or mm⁴
xx
position along the member, the variable you integrate overft or m

Watch out: Keep the sign convention the same for the unit-load and real-load forces; a member in tension under one and compression under the other contributes a negative term.

Standard Beam Deflections

Handbook 10.6, pp. 140–141
δ=PL348EI,5wL4384EI,PL33EI\delta = \frac{PL^3}{48EI}, \quad \frac{5wL^4}{384EI}, \quad \frac{PL^3}{3EI}

Maximum deflection of three common cases: a simple beam with a point load at midspan, a simple beam with a full uniform load, and a cantilever with a point load at the free end.

δ\delta
maximum deflection (at midspan for the simple beams, at the free end for the cantilever)in. or mm
PP
concentrated (point) loadkips or kN
LL
span length (beam length for the cantilever)in. or mm
EE
modulus of elasticity of the beam materialksi or MPa
II
moment of inertia of the beam cross section about the bending axisin⁴ or mm⁴
ww
uniformly distributed loadkips/in. or kN/mm (convert from kips/ft)

Watch out: Units must match: with E in ksi and I in in⁴, L must be in inches and w in kips per inch, so divide a kips/ft load by 12 and multiply L in feet by 12.

Propped Cantilever / Fixed-End Moment

Handbook 10.6, p. 277
Rprop=3wL8,MFE=wL212R_{\text{prop}} = \frac{3wL}{8}, \quad M_{FE} = \frac{wL^2}{12}

Prop reaction of a cantilever with a uniform load and a roller at the free end, and the fixed-end moment of a beam fixed at both ends under a uniform load.

RpropR_{\text{prop}}
vertical reaction at the propped (roller) end of a cantilever carrying a full uniform loadkips or kN
ww
uniformly distributed loadkips/ft or kN/m
LL
span lengthft or m
MFEM_{FE}
fixed-end moment at each end of a beam fixed at both ends under a full uniform loadkip·ft or kN·m

Watch out: The fixed-end moment wL²/12 is for a beam fixed at both ends; the fixed end of a propped cantilever carries wL²/8, not wL²/12.

LRFD Basic Combination

Handbook 10.6, p. 278
1.2D + 1.6L

Factored (ultimate) load for strength design when the loads are dead and floor live load.

DD
dead load: self weight and permanent attachmentskips, kips/ft, lb/ft² or kN, kN/m, kPa
LL
floor live load: occupants, furniture and other movable loadssame unit as D

Watch out: This is one of several combinations; always also check 1.4D, which governs when dead load is large compared with live load, and use the largest result.

RC Beam Moment Capacity

Handbook 10.6, p. 281
Mn=Asfy(d−a/2)M_n = A_s f_y (d - a/2)

Nominal bending strength of a singly reinforced rectangular concrete beam where the tension steel yields.

MnM_n
nominal flexural strength of the section, before the φ factorin.-lb or kip·in. (N·mm in SI)
AsA_s
area of longitudinal tension reinforcementin² or mm²
fyf_y
yield strength of the reinforcing steelpsi or ksi (MPa in SI)
dd
effective depth, from the extreme compression fiber to the centroid of the tension steelin. or mm
aa
depth of the equivalent rectangular (Whitney) stress blockin. or mm

Watch out: The design strength is φMn, with φ = 0.9 only when the section is tension-controlled (εt ≥ 0.005); compare φMn, not Mn, to Mu.

Whitney Stress Block Depth

Handbook 10.6, p. 281
a=Asfy0.85fc′ba = \frac{A_s f_y}{0.85 f_c' b}

Depth of the equivalent compression block in a singly reinforced rectangular concrete beam, found by setting steel tension equal to concrete compression.

aa
depth of the equivalent rectangular stress blockin. or mm
AsA_s
area of longitudinal tension reinforcementin² or mm²
fyf_y
yield strength of the reinforcing steelpsi or ksi (MPa in SI)
fc′f_c'
specified 28-day compressive strength of the concretepsi or ksi (MPa in SI)
bb
width of the compression face of the beamin. or mm

Watch out: a is not the neutral axis depth c; c = a/β1, and β1 is 0.85 only for f′c up to 4,000 psi.

Concrete Shear Capacity

Handbook 10.6, p. 282
Vc=2λfc′⋅bw⋅dV_c = 2\lambda\sqrt{f_c'} \cdot b_w \cdot d

Nominal shear strength carried by the concrete alone in a reinforced concrete beam, before adding stirrups.

VcV_c
nominal shear strength provided by the concretelb
λ\lambda
lightweight concrete factor: 1.0 for normal weight, 0.75 for lightweightunitless
fc′f_c'
specified compressive strength of the concretepsi (must be psi in this equation)
bwb_w
web width of the beamin.
dd
effective depth, from the compression face to the centroid of the tension steelin.

Watch out: The constant 2 assumes f′c in psi, so take the root of 4,000 (not 4) and read the answer in pounds before converting to kips.

RC Column Max Capacity

Handbook 10.6, p. 284
ϕPn(max⁡)=0.80ϕ[0.85fc′(Ag−Ast)+fyAst]\phi P_{n(\max)} = 0.80\phi[0.85 f_c'(A_g - A_{st}) + f_y A_{st}]

Maximum design axial strength of a short tied reinforced concrete column loaded with no significant moment.

ϕPn(max⁡)\phi P_{n(\max)}
maximum design axial compressive strength of the columnlb or kips (N or kN in SI)
ϕ\phi
strength reduction factor, 0.65 for tied columns (compression-controlled)unitless
fc′f_c'
specified compressive strength of the concretepsi or ksi (MPa in SI)
AgA_g
gross area of the concrete sectionin² or mm²
AstA_{st}
total area of longitudinal reinforcementin² or mm²
fyf_y
yield strength of the reinforcing steelpsi or ksi (MPa in SI)

Watch out: Subtract the steel area from Ag in the concrete term, and do not forget the 0.80 factor on top of φ = 0.65.

Steel Plastic Moment

Handbook 10.6, p. 287
Mp=FyZxM_p = F_y Z_x

Nominal flexural strength of a compact, laterally braced steel I-beam bent about its strong axis (yielding limit state).

MpM_p
plastic moment, the moment when the whole section has yieldedkip·in. (divide by 12 for kip·ft)
FyF_y
specified minimum yield stress of the steel, 50 ksi for most W shapesksi or MPa
ZxZ_x
plastic section modulus about the strong (x) axisin³ or mm³

Watch out: Use the plastic modulus Z, not the elastic modulus S, and remember the design strength is 0.90 Mp; this only holds when the unbraced length Lb ≤ Lp.

Steel Column Strength

Handbook 10.6, p. 287
ϕcPn=ϕcFcrAg\phi_c P_n = \phi_c F_{cr} A_g

Design compressive strength of a steel column for flexural buckling, once you know the critical stress from KL/r.

ϕc\phi_c
resistance factor for compression, 0.90unitless
PnP_n
nominal compressive strengthkips or kN
FcrF_{cr}
critical buckling stress, from the AISC equations or table using KL/rksi or MPa
AgA_g
gross area of the column cross sectionin² or mm²

Watch out: Use the larger slenderness KL/r of the two axes (usually the weak y axis) to get Fcr; using rx overstates the strength.

Steel Tension Members

Handbook 10.6, p. 289
Pn=FyAg (yield),Pn=FuAe (rupture)P_n = F_y A_g \text{ (yield)}, \quad P_n = F_u A_e \text{ (rupture)}

Nominal strength of a steel tension member, checked for yielding on the gross section and rupture on the effective net section.

PnP_n
nominal tensile strength for the limit state being checkedkips or kN
FyF_y
specified minimum yield stressksi or MPa
AgA_g
gross area of the memberin² or mm²
FuF_u
specified minimum tensile (ultimate) strengthksi or MPa
AeA_e
effective net area, U times the net area An after holes are removedin² or mm²

Watch out: The two checks use different φ factors (0.90 for yielding, 0.75 for rupture); apply each one before picking the smaller strength.

Effective Stress

Handbook 10.6, p. 269
σ′=σ−u\sigma' = \sigma - u

Find the stress carried by the soil grains at a depth, which is what controls strength and settlement.

σ′\sigma'
effective stress, the part of the stress carried grain to grainlb/ft² or kPa
σ\sigma
total stress, the sum of unit weight times thickness for every layer above the point (plus any surcharge)lb/ft² or kPa
uu
pore water pressure, unit weight of water times the depth below the water tablelb/ft² or kPa

Watch out: Below the water table use the saturated unit weight for total stress and then subtract u; using the buoyant unit weight and also subtracting u counts the water twice.

Phase Relation (master equation)

Handbook 10.6, p. 266
Se=ωGsSe = \omega G_s

Link saturation, void ratio, water content and specific gravity, so you can find any one when you know the other three.

SS
degree of saturation, the fraction of the voids filled with waterunitless (decimal, 1.0 when saturated)
ee
void ratio, volume of voids divided by volume of solidsunitless
ω\omega
water content, weight of water divided by weight of solidsunitless (decimal)
GsG_s
specific gravity of the soil solids, usually about 2.65 to 2.75unitless

Watch out: Use S and ω as decimals, not percents, on both sides; mixing 25% with 0.25 makes e off by a factor of 100.

Saturated Unit Weight

Handbook 10.6, p. 265
γsat=(Gs+e)γw1+e\gamma_{sat} = \frac{(G_s + e)\gamma_w}{1 + e}

Unit weight of a soil whose voids are completely full of water, from its specific gravity and void ratio.

γsat\gamma_{sat}
saturated unit weight of the soillb/ft³ or kN/m³
GsG_s
specific gravity of the soil solidsunitless
ee
void ratiounitless
γw\gamma_w
unit weight of water, 62.4 lb/ft³ or 9.81 kN/m³lb/ft³ or kN/m³

Watch out: Do not confuse it with dry unit weight, Gs γw/(1 + e), which has no e in the numerator.

NC Consolidation Settlement

Handbook 10.6, p. 267
ΔH=H01+e0Cclog⁡p0+Δpp0\Delta H = \frac{H_0}{1+e_0} C_c \log \frac{p_0 + \Delta p}{p_0}

Primary consolidation settlement of a normally consolidated clay layer under a new load.

ΔH\Delta H
settlement (change in thickness) of the clay layerft or m (often reported in in. or mm)
H0H_0
initial thickness of the clay layerft or m
e0e_0
initial void ratio of the clay, before the loadunitless
CcC_c
compression index, the slope of the virgin compression line on an e versus log p plotunitless
p0p_0
initial effective vertical stress at the middle of the clay layerlb/ft² or kPa
Δp\Delta p
added stress at the middle of the clay layer from the new loadlb/ft² or kPa

Watch out: Compute p0 with effective stress at the middle of the layer, and use Cr instead of Cc for any part of the load below the preconsolidation pressure.

Mohr-Coulomb Failure

Handbook 10.6, p. 269
τf=c′+σ′tan⁡ϕ′\tau_f = c' + \sigma' \tan \phi'

Shear strength of a soil on a plane, from its cohesion, friction angle and the effective normal stress on that plane.

τf\tau_f
shear strength (shear stress at failure) on the planelb/ft² or kPa
c′c'
effective cohesion, the intercept of the failure envelopelb/ft² or kPa
σ′\sigma'
effective normal stress on the failure planelb/ft² or kPa
ϕ′\phi'
effective angle of internal frictiondegrees

Watch out: Clean sands have c′ = 0, and the normal stress must be on the failure plane, not the major principal stress σ1.

Terzaghi's Bearing Capacity

Handbook 10.6, p. 270
qult=cNc+γ′DfNq+0.5γ′BNγq_{ult} = cN_c + \gamma' D_f N_q + 0.5\gamma' BN_\gamma

Ultimate bearing capacity of a shallow strip footing, from cohesion, embedment depth and footing width.

qultq_{ult}
ultimate bearing capacity, the pressure that causes shear failure under the footinglb/ft² or kPa
cc
cohesion of the soil under the footinglb/ft² or kPa
NcN_c
bearing capacity factor for cohesion, read from a table using φunitless
γ′\gamma'
effective unit weight of the soil (buoyant unit weight where it is below the water table)lb/ft³ or kN/m³
DfD_f
depth of the footing base below the ground surfaceft or m
NqN_q
bearing capacity factor for the overburden (depth) term, read from a table using φunitless
BB
width of the strip footingft or m
NγN_\gamma
bearing capacity factor for the soil weight term, read from a table using φunitless

Watch out: Where the water table is at or above the footing base, use the buoyant unit weight (γsat minus γw) in the B term, not the total unit weight.

Rankine Active Pressure

Handbook 10.6, p. 269
Ka=tan⁡2(45°−ϕ/2)K_a = \tan^2(45\degree - \phi/2)

Active earth pressure coefficient behind a smooth wall with level, cohesionless backfill.

KaK_a
Rankine active earth pressure coefficient, the ratio of horizontal to vertical effective stressunitless
ϕ\phi
angle of internal friction of the backfilldegrees

Watch out: Active uses minus (45° − φ/2) and passive uses plus (45° + φ/2); Ka is less than 1 and Kp is greater than 1.

Retaining Wall Overturning

Handbook 10.6, p. 270
FSoverturning=ΣMR/MOFS_{\text{overturning}} = \Sigma M_R / M_O

Factor of safety of a retaining wall against tipping over about its toe.

FSoverturningFS_{\text{overturning}}
factor of safety against overturning, typically required to be 1.5 to 2 or moreunitless
MRM_R
resisting moment about the toe from the wall and soil weights; the Σ means add every onekip·ft/ft or kN·m/m
MOM_O
overturning moment about the toe from the lateral earth (and water) pressurekip·ft/ft or kN·m/m

Watch out: Take every moment about the toe, and place each triangular pressure resultant at one third of its height from the bottom.

Darcy's Law

Handbook 10.6, p. 298
q=k i Aq = k\,i\,A

Flow rate of water through a soil sample or aquifer under a hydraulic gradient.

qq
flow rate (discharge) through the soilft³/s or m³/s
kk
hydraulic conductivity (coefficient of permeability)ft/s or m/s (often given in cm/s)
ii
hydraulic gradient, head loss divided by flow lengthunitless
AA
total cross-sectional area of soil perpendicular to the flowft² or m²

Watch out: A is the full soil area, not just the voids; the actual seepage velocity is k i divided by the porosity n.

Flow-Net Seepage

Not in the handbook: memorize it
q=k H Nf/Ndq = k\,H\,N_f/N_d

Seepage under a dam or sheet pile wall per unit length of the structure, counted from a flow net.

qq
seepage per unit length of the structureft³/s per ft or m³/s per m
kk
hydraulic conductivity of the soilft/s or m/s
HH
total head loss, the difference between upstream and downstream water levelsft or m
NfN_f
number of flow channels (spaces between flow lines)unitless
NdN_d
number of equipotential drops (spaces between equipotential lines)unitless

Watch out: Count the spaces between lines, not the lines themselves, and put flow channels on top and drops on the bottom.

Critical Hydraulic Gradient

Handbook 10.6, p. 266
ic=Gs−11+ei_c = \frac{G_s - 1}{1 + e}

Upward gradient at which effective stress drops to zero and sand boils (quick condition).

ici_c
critical hydraulic gradient, often close to 1.0unitless
GsG_s
specific gravity of the soil solidsunitless
ee
void ratiounitless

Watch out: The handbook writes it as (γsat − γw)/γw, which is the same value; the factor of safety against boiling is ic divided by the actual exit gradient.

Infinite Slope (dry, cohesionless)

Not in the handbook: memorize it
FS=tan⁡ϕtan⁡βFS = \frac{\tan\phi}{\tan\beta}

Factor of safety of a long, dry slope in clean sand against sliding parallel to the surface.

FSFS
factor of safety against slidingunitless
ϕ\phi
angle of internal friction of the soildegrees
β\beta
slope angle measured from the horizontaldegrees

Watch out: This form holds only for dry (or fully submerged) sand with no cohesion; seepage parallel to the slope roughly halves the factor of safety.

Relative Compaction

Handbook 10.6, p. 266
RC=γd,fieldγd,max×100RC = \frac{\gamma_{d,field}}{\gamma_{d,max}} \times 100

Check whether a compacted fill meets the specified percent of the lab maximum dry unit weight.

RCRC
relative compactionpercent
γd,field\gamma_{d,field}
dry unit weight measured in the fieldlb/ft³ or kN/m³
γd,max\gamma_{d,max}
maximum dry unit weight from the lab Proctor testlb/ft³ or kN/m³

Watch out: Field tests often report the moist (wet) unit weight; convert it to dry first by dividing by (1 + ω).

Relative Density

Handbook 10.6, p. 266
Dr=emax−eemax−emin×100D_r = \frac{e_{max} - e}{e_{max} - e_{min}} \times 100

How dense a granular soil is compared with its loosest and densest possible states.

DrD_r
relative densitypercent
emaxe_{max}
void ratio in the loosest stateunitless
ee
void ratio in the current (field) stateunitless
emine_{min}
void ratio in the densest stateunitless

Watch out: The numerator uses e max, so a high void ratio gives a low relative density; flipping it gives 100% minus the right answer.

Pile Capacity (end bearing + skin friction)

Not in the handbook: memorize it
Qult=Qp+QsQ_{ult} = Q_p + Q_s

Ultimate axial capacity of a single pile as the sum of tip resistance and side resistance.

QultQ_{ult}
ultimate axial load capacity of the pilekips or kN
QpQ_p
end bearing, the tip resistance (unit tip resistance times tip area)kips or kN
QsQ_s
skin friction, the side resistance (unit side friction times pile perimeter times embedded length, summed over layers)kips or kN

Watch out: This is the ultimate capacity; divide by the factor of safety (often 2 to 3) for the allowable load.

Transportation Eng.

Study guidePractice problems

Stopping Sight Distance

Handbook 10.6, p. 306
SSD=1.47Vt+V230(a32.2±G)SSD = 1.47 V t + \frac{V^2}{30\left(\frac{a}{32.2} \pm G\right)}

Distance a driver needs to see ahead to perceive a hazard, react, and brake to a stop on a grade.

SSDSSD
stopping sight distance, reaction distance plus braking distanceft
VV
design speedmph
tt
driver perception-reaction time, 2.5 s for AASHTO designsec
aa
deceleration rate, 11.2 ft/s² for AASHTO designft/s²
GG
grade as a decimal (percent grade divided by 100), plus for uphill and minus for downhillunitless

Watch out: G is a decimal, so a 3% downgrade is −0.03, and a downgrade makes the braking distance longer, not shorter.

Crest Vertical Curve (S ≤ L)

Handbook 10.6, p. 308
L=AS22,158L = \frac{A S^2}{2{,}158}

Minimum length of a crest vertical curve that provides sight distance S, when the sight distance fits within the curve.

LL
length of the vertical curve, measured horizontallyft
AA
algebraic difference in grades, g2 minus g1, as an absolute value in percentpercent (use 4 for 4%, not 0.04)
SS
sight distance to provide, usually the stopping sight distanceft

Watch out: The 2,158 assumes h1 = 3.5 ft and h2 = 2.0 ft and S ≤ L; if your answer comes out shorter than S, redo it with the S > L equation.

Horizontal Curve Radius

Handbook 10.6, p. 308
R=5,729.58DR = \frac{5{,}729.58}{D}

Convert between degree of curve (arc definition) and radius for a horizontal curve.

RR
radius of the curveft
DD
degree of curve, the central angle that subtends a 100 ft arcdegrees

Watch out: D must be in decimal degrees, so convert minutes first (4°30′ is 4.5°).

Yellow Signal Interval

Handbook 10.6, p. 306
y=t+v2a±64.4Gy = t + \frac{v}{2a \pm 64.4G}

Length of the yellow change interval at a signalized intersection.

yy
yellow interval, rounded to the nearest 0.1 ssec
tt
driver perception-reaction time, typically 1.0 ssec
vv
vehicle approach speedft/s
aa
deceleration rate, typically 10 ft/s²ft/s²
GG
grade as a decimal (percent grade divided by 100), plus for uphillunitless

Watch out: v is in ft/s here, not mph; multiply mph by 1.47 first.

Maximum Flow (Greenshields)

Handbook 10.6, p. 312
Vm=DjSf4V_m = \frac{D_j S_f}{4}

Maximum flow (capacity) of a traffic stream under the Greenshields linear speed-density model.

VmV_m
maximum flow (capacity)veh/hr/ln
DjD_j
jam density, density when traffic is stoppedveh/mi/ln
SfS_f
free-flow speed, speed at near-zero densitymph

Watch out: Maximum flow happens at half the jam density and half the free-flow speed, not at either extreme.

Demand Flow Rate

Handbook 10.6, p. 311
vp=VPHF×N×fHVv_p = \frac{V}{PHF \times N \times f_{HV}}

Convert an hourly volume into a peak 15-minute flow rate per lane in passenger cars, for freeway level of service.

vpv_p
demand flow rate under equivalent base conditionspc/h/ln
VV
hourly demand volume in the analysis directionveh/h
PHFPHF
peak hour factor, hourly volume divided by four times the peak 15-min volumeunitless (at most 1.0)
NN
number of lanes in the analysis directionunitless
fHVf_{HV}
heavy-vehicle adjustment factor, 1 / [1 + PT(ET − 1)]unitless (at most 1.0)

Watch out: Use the lanes in one direction only, and remember fHV is below 1, so it increases the flow rate.

AASHTO Structural Number

Handbook 10.6, p. 314
SN=a1D1+a2D2m2+a3D3m3SN = a_1 D_1 + a_2 D_2 m_2 + a_3 D_3 m_3

Structural capacity of a flexible pavement from the thickness, strength and drainage of each layer.

SNSN
structural number of the whole pavementunitless (index)
a1a_1
layer coefficient of the surface course (asphalt)per inch
D1D_1
thickness of the surface coursein.
a2a_2
layer coefficient of the base courseper inch
D2D_2
thickness of the base coursein.
m2m_2
drainage coefficient of the base course, 1.0 unless givenunitless
a3a_3
layer coefficient of the subbase courseper inch
D3D_3
thickness of the subbase coursein.
m3m_3
drainage coefficient of the subbase course, 1.0 unless givenunitless

Watch out: Thicknesses must be in inches, and the surface layer has no drainage coefficient.

Average End Area Volume

Handbook 10.6, p. 315
V=L(A1+A2)2V = \frac{L(A_1 + A_2)}{2}

Earthwork volume between two cross sections a known distance apart.

VV
volume of cut or fill between the two sectionsft³ (divide by 27 for yd³) or m³
LL
distance between the two cross sectionsft or m
A1A_1
area of the first cross sectionft² or m²
A2A_2
area of the second cross sectionft² or m²

Watch out: Earthwork is usually asked in cubic yards, so divide cubic feet by 27, not by 9 or 3.

Gravity Model (Trip Distribution)

Handbook 10.6, p. 312
Tij=PiAjFijKij∑jAjFijKijT_{ij} = P_i \frac{A_j F_{ij} K_{ij}}{\sum_j A_j F_{ij} K_{ij}}

Split the trips produced in one zone among the destination zones in proportion to attractions and travel impedance.

TijT_{ij}
number of trips produced in zone i and attracted to zone jtrips
PiP_i
total trips produced in zone itrips
AjA_j
trips attracted to zone jtrips
FijF_{ij}
friction factor, which gets smaller as the travel time between i and j growsunitless
KijK_{ij}
socioeconomic adjustment factor for travel between i and j, 1.0 unless givenunitless

Watch out: The denominator sums over every destination zone j, including the one you are solving for.

Early Finish

Handbook 10.6, p. 316
EF=ES+DEF = ES + D

Forward pass of a CPM schedule: the earliest an activity can finish.

EFEF
early finish of the activitydays (any consistent time unit)
ESES
early start, the latest early finish among all its predecessorsdays
DD
duration of the activitydays

Watch out: When an activity has several predecessors, its ES is the largest of their EF values, not the smallest.

Late Start

Handbook 10.6, p. 316
LS=LF−DLS = LF - D

Backward pass of a CPM schedule: the latest an activity can start without delaying the project.

LSLS
late start of the activitydays (any consistent time unit)
LFLF
late finish, the earliest late start among all its successorsdays
DD
duration of the activitydays

Watch out: On the backward pass an activity with several successors takes the smallest of their LS values as its LF.

Total Float

Handbook 10.6, p. 316
TF=LS−ES=LF−EFTF = LS - ES = LF - EF

How long an activity can slip without delaying the whole project; zero total float marks the critical path.

TFTF
total float of the activitydays (any consistent time unit)
LSLS
late startdays
ESES
early startdays
LFLF
late finishdays
EFEF
early finishdays

Watch out: Total float is shared along a path, so using it on one activity can use up the float of the activities after it.

Free Float

Not in the handbook: memorize it
FF=min⁡(ESj)−EFiFF = \min(ES_j) - EF_i

How long an activity can slip without delaying the early start of any activity that follows it.

FFFF
free float of activity idays (any consistent time unit)
ESjES_j
early start of a successor activity j; take the smallest onedays
EFiEF_i
early finish of the activity i you are checkingdays

Watch out: Free float uses early dates only (successor ES minus your EF); it can never be larger than total float.

Cost Variance

Handbook 10.6, p. 316
CV=BCWP−ACWPCV = BCWP - ACWP

Whether the work done so far cost more or less than budgeted.

CVCV
cost variance; negative means over budgetdollars
BCWPBCWP
budgeted cost of work performed (earned value)dollars
ACWPACWP
actual cost of work performed (actual cost)dollars

Watch out: Both variances start with earned value (BCWP); a negative CV is bad, it means over budget.

Schedule Variance

Handbook 10.6, p. 316
SV=BCWP−BCWSSV = BCWP - BCWS

Whether more or less work has been done than planned by this date, measured in dollars.

SVSV
schedule variance; negative means behind scheduledollars
BCWPBCWP
budgeted cost of work performed (earned value)dollars
BCWSBCWS
budgeted cost of work scheduled (planned value)dollars

Watch out: SV compares earned with planned, never with actual cost; actual cost belongs only in the cost measures.

Cost Performance Index

Handbook 10.6, p. 317
CPI=BCWPACWPCPI = \frac{BCWP}{ACWP}

Cost efficiency of the work so far, as earned value per dollar actually spent.

CPICPI
cost performance index; below 1.0 means over budgetunitless
BCWPBCWP
budgeted cost of work performed (earned value)dollars
ACWPACWP
actual cost of work performed (actual cost)dollars

Watch out: Earned value always goes on top; flipping the ratio turns an over-budget job into one that looks under budget.

Schedule Performance Index

Handbook 10.6, p. 317
SPI=BCWPBCWSSPI = \frac{BCWP}{BCWS}

Schedule efficiency of the work so far, as earned value per dollar of work planned by now.

SPISPI
schedule performance index; below 1.0 means behind scheduleunitless
BCWPBCWP
budgeted cost of work performed (earned value)dollars
BCWSBCWS
budgeted cost of work scheduled (planned value)dollars

Watch out: Earned value goes on top here too; SPI below 1.0 means behind schedule.

Estimate to Complete

Handbook 10.6, p. 317
ETC=BAC−BCWPCPIETC = \frac{BAC - BCWP}{CPI}

Forecast of the cost to finish the remaining work, assuming the current cost efficiency continues.

ETCETC
estimate to complete, the forecast cost of the remaining workdollars
BACBAC
budget at completion, the original total project budgetdollars
BCWPBCWP
budgeted cost of work performed (earned value) to datedollars
CPICPI
cost performance index, BCWP divided by ACWPunitless

Watch out: Subtract the earned value (BCWP) from BAC, not the actual cost spent so far.

Estimate at Completion

Handbook 10.6, p. 317
EAC=ACWP+ETCEAC = ACWP + ETC

Forecast of the total project cost at the end: what has been spent plus what remains.

EACEAC
estimate at completion, the forecast final cost of the projectdollars
ACWPACWP
actual cost of work performed to datedollars
ETCETC
estimate to complete the remaining workdollars

Watch out: Add the actual cost to date, not the earned value, to the ETC.

Knowing the formula is half of it

The other half is spotting which one a problem wants. Practice that on worked FE Civil problems across all 15 topics. Completely free.

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